Don't know if I'm totally correct...
1) I'd say the speed of a man at the equator would be (2 . pi . 6400 km) / 24h , seeing as the earth turns around in 24 hours.
2) This is a long time ago... with the speed you've just calculated, the radius, and his weight, you would be able to calculate that force
3) The weight of the man would be 97 kg . 9.81 N/kg
4) The force holding him to the surface would be gravity, so Fz = m . g . h = 97 kg . 9.81 N/kg . 6400 km